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H3C Large-Scale Routing Network Technologies V2.0 Sample Questions:
1. 在图示网络中,各路由器间 BGP 路由学习正常, BGP 路由属性都去缺省值。
在 RTA 上将路由 100.10.1.0/24 引入 BGP 中后, RTD 的 BGP 路由表中 100.10.1.0/24 的下一跳是 ______?
A) RTB
B) RTA
C) RTE
D) RTC
2. 在图所示网络中, PTA 的缺省下一跳为 RTC ,且 PBR 配置如下:
polic-based-route pbr_a permit node 10
if-match acl 3000
appldefault output-interface serial 2/0
polic-based-route pbr_a dennode 20
根据上述配置,关于 RTA 上匹配 Acl 3000 的数据流,说法错误的是 ?
A) 当网络中所有链路正常时,报文将被发往 PTB
B) 当网络中所有链路正常时,报文将被发往 PTC
C) 当 PTA 和 PTC 同时链路故障时,报文将被发往 PTB
D) 当 PTA 和 PTC 同时链路故障时,报文将被丢弃
3. 关于 OSPF 协议与 RIP 协议的比较,下列哪些说法是正确的 ?
A) OSPF 的安全性比 RIP 低
B) OSPF 的收敛速度比 RIP 快
C) OSPF 的可靠性比 RIP 高
D) 部署 OSPF 的网络扩展性比部署 RIP 的网络好
4. 如图所示, MSR 路由器以太接口 E1/0 的实际带宽为 10Mbps ,串口 S2/0 的实际链路带宽为 64Kbps 。
为了优先使用高带宽链路,并达到路由备份的目的,以下哪个方案最合理 ?
A) 以太接口运行 RIP 协议。再设置静态路由,出接口为串口 S2/0 ,优先级值设定为 80
B) 设置静态路由,出接口为串口 S2/0 和以太接口 E1/0 ,优先级值设定相同
C) 以太接口运行 OSPF 协议。再设置静态路由,出接口为串口 S2/0 ,优先级值设定为 80
D) 以太接口 E1/0 和串口 S2/0 都运行 RIP 协议
5. 在如图所示的拓扑中, RTA 、 RTB 、 RTC 上分别执行如下配置:
RTA]ospf 1
RTA-ospf-1]area 1
RTA-ospf-1-area-0.0.0.1]network 10.0.0.0 0.0.0.255
RTB]ospf 1
RTB-ospf-1]area 1
RTB-ospf-1-area-0.0.0.1]network 10.0.0.0 0.0.0.255
RTB-ospf-1-area-0.0.0.1]area 0
RTB-ospf-1-area-0.0.0.0]network 20.0.0.0 0.0.0.255
RTC]ospf 1
RTC-ospf-1]area 0
RTC-ospf-1-area-0.0.0.0]network 20.0.0.0 0.0.0.255
RTC-ospf-1-area-0.0.0.0]area 2
RTC-ospf-1-area-0.0.0.2]stub
RTC-ospf-1-area-0.0.0.2]network 30.0.0.0 0.0.0.255
如要使 RTD 可以学习到路由 10.0.0.0/24 ,则需要如何配置 ?
A) RTD]ospf 1 RTD-ospf-1]area 2 RTD-ospf-1-area-0.0.0.2]network 20.0.0.0 0.0.0.255 RTD-ospf-1-area-0.0.0.2]stub
B) RTD]ospf 1 RTD-ospf-1]area 2 RTD-ospf-1-area-0.0.0.2]network 30.0.0.0 0.0.0.255 RTD-ospf-1-area-0.0.0.2]area 0 RTD-ospf-1-area-0.0.0.0]stub
C) RTD]ospf 1 RTD-ospf-1]area 2 RTD-ospf-1-area-0.0.0.2]network 30.0.0.0 0.0.0.255 RTD-ospf-1-area-0.0.0.2]stub
D) RTD]ospf 1 RTD-ospf-1]area 2 RTD-ospf-1-area-0.0.0.2]network 30.0.0.0 0.0.0.255
Solutions:
| Question # 1 Answer: B | Question # 2 Answer: A,D | Question # 3 Answer: B,C,D | Question # 4 Answer: C | Question # 5 Answer: C |

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