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Make regular plans and achieve success effectively. The Oracle Database SQL exam torrent from PracticeVCE makes planning easy: 437 practice questions for the 1z1-071 exam, delivered the minute you pay.

Oracle 1z1-071 Exam Syllabus Topics:

SectionWeightObjectives
Using DDL Statements to Create and Manage Tables14%- Create a simple table
- Categorize the main database objects
- Drop, rename, and truncate tables
- Alter table definitions
- Describe the data types that are available for columns
- Review the table structure
Using Conversion Functions and Conditional Expressions10%- Describe implicit and explicit data type conversion
- Use conditional IF THEN ELSE logic in a SELECT statement
- Apply the NVL, NULLIF, and COALESCE functions to data
- Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions
Retrieving Data Using the SQL SELECT Statement5%- List the capabilities of SQL SELECT statements
- Differentiate between SQL statements and SQL*Plus commands
- Execute a basic SELECT statement
Using Set Operators5%- Describe the order of precedence when the set operators are used
- Use a set operator to combine multiple queries into a single query
- Describe set operators
Using Subqueries to Solve Queries15%- List the types of subqueries
- Describe the types of problems that subqueries can solve
- Define subqueries
- Write single-row and multi-row subqueries
Using Single-Row Functions to Customize Output10%- Manipulate strings with character function in the SELECT and WHERE clauses
- Manipulate numbers with the ROUND, TRUNC, and MOD functions
- Manipulate dates with the date functions
- Describe the differences between single-row and multiple-row functions
- Perform arithmetic with date data
Creating Other Schema Objects10%- Create synonyms for database objects
- Create, maintain, and use sequences
- Create, modify, and retrieve data from a view
- Create and maintain indexes
Controlling User Access5%- Distinguish between granting privileges and roles
- Differentiate system privileges from object privileges
- Grant privileges on tables and on a view
Displaying Data from Multiple Tables Using Joins15%- Write SELECT statements to access data from more than one table using equijoins and non-equijoins
- Cross join tables
- Join a table to itself by using a self-join
- View data that does not meet a join condition by using outer joins
Working with Oracle Database SQL8%- Start up and shut down a database
- Explain the installation of Oracle Database software
- Create a container database
- Describe the Oracle Database architecture
Manipulating Data14%- Delete rows from a table
- Control transactions
- Update rows in a table
- Describe each data manipulation language (DML) statement
- Insert rows into a table
Reporting Aggregated Data Using Group Functions15%- Identify the available group functions
- Describe the use of group functions
- Group data by using the GROUP BY clause
- Include or exclude grouped rows by using the HAVING clause
Restricting and Sorting Data6%- Use ampersand substitution to restrict and sort output at runtime
- Limit the rows that are retrieved by a query
- Sort the rows that are retrieved by a query
- Use DEFINE and UNDEFINE commands

1z1-071 Exam FAQ — Become the Elite

The Oracle Database SQL is Oracle's certification exam for Oracle PL/SQL Developer Certified Associate, at the Associate level. The certificate is an indispensable part of becoming an elite in this field — priority in salary, outlook, and promotion follows it. Related credentials include Oracle Database Administrator Certified Associate (DBA), Oracle Database SQL Certified Associate.

Right after you place your order, our system emails the Oracle Database SQL material automatically — about a minute, so you can download and begin your practice plans immediately, with 24/7 help if nothing arrives within 2 hours. If you fail the corresponding 1z1-071 exam within 60 days of purchase, we return your full amount: send a scanned enrollment slip plus the official Score Report PDF within 2 days of the exam, processed within 7 days. Excluded: exams within 3 days of purchase, candidate names that don't match the payer, and free or expired products. Or exchange for two equal-value products free.

$245 USD per attempt, 63% to pass. Retakes cost the full fee again — plan your preparation regularly with the 437 practice questions for the 1z1-071 exam at PracticeVCE.

Yes — download the free Oracle Database SQL demo before paying; the full torrent goes well beyond it. Purchases include 365 days of free updates by email; renew afterward at 50% off.

120 minutes for 70 questions. Rich functions in the PracticeVCE software and app engines — timed modes and progress tracking — build the pacing you need.

The Oracle Database SQL blueprint spans 13 domains — including Creating Other Schema Objects (10%), Using DDL Statements to Create and Manage Tables (14%), Working with Oracle Database SQL (8%). Plan practice around the heavier domains; the complete outline above lists every subtopic.

No formal prerequisites required, but basic knowledge of relational database concepts is recommended Eligibility rules change over time, so verify the current requirements on the official page (official 1z1-071 exam page) before registering.

Oracle Database SQL Sample Questions:

In the customers table, the CUST_CITY column contains the value 'Paris' for the CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:

What would be the outcome?

  • A. Abigail IS
  • B. An error message
  • C. Abigail Pa
  • D. Abigail PA
Reveal Solution  Discussion  0

Correct Answer: C  🗳️

Using the CUSTOMERS table, you need to generate a report that shows 50% of each credit amount in each income level. The report should NOT show any repeated credit amounts in each income level.
Which query would give the required result?

  • A. SELECT cust_income_level || ` ' || cust_credit_limit * 0.50 AS "50% Credit Limit" FROM customers.
  • B. SELECT DISTINCT cust_income_level || ` ' || cust_credit_limit * 0.50 AS "50% Credit Limit" FROM customers.
  • C. SELECT DISTINCT cust_income_level, DISTINCT cust_credit_limit * 0.50 AS "50% Credit Limit" FROM customers.
  • D. SELECT cust_income_level, DISTINCT cust_credit_limit * 0.50 AS "50% Credit Limit" FROM customers
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Which three statements are true about the Oracle join and ANSI join syntax? (Choose three.)

  • A. The Oracle join syntax supports creation of a Cartesian product of two tables.
  • B. The Oracle join syntax performs less well than the SQL:1999 compliant ANSI join syntax.
  • C. The Oracle join syntax performs better than the SQL:1999 compliant ANSI join syntax.
  • D. The Oracle join syntax supports natural joins.
  • E. The SQL:1999 compliant ANSI join syntax supports natural joins.
  • F. The Oracle join syntax only supports right outer joins.
  • G. The SQL:1999 compliant ANSI join syntax supports creation of a Cartesian product of two tables.
Reveal Solution  Discussion  0

Correct Answer: A,E,G  🗳️

Explanation: Only visible for PracticeVCE members. You can sign-up / login (it's free).

Examine the data in the PRODUCTStable:

Examine these queries:

Which queries generate the same output?

  • A. 2 and 3
  • B. 1 and 2
  • C. 1, 2, and 3
  • D. 1 and 3
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

Explanation: Only visible for PracticeVCE members. You can sign-up / login (it's free).

View the exhibit and examine the data in the PROJ_TASK_DETAILS table. (Choose the best answer.)

The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them.
The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result?

  • A. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p JOIN proj_task_details d
    ON (p.based_on = d.task_id);
  • B. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p LEFT OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
  • C. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p FULL OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
  • D. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p JOIN proj_task_details d
    ON (p.task_id = d.task_id);
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

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